Laskuja

n(HCl) = 

0 ,680 g CaCO3 --> Ca2+ CO3 2-

2 HCl + CaCO3 --> CaCl2

n(HCl) = 0,680*2/(1,008+35,45) = 0,0373 mol

Konsentraatio = 0,15*1000/(1,008+35,45)/1 = 4,11 mol/l

V(HCl) = 0,0373 mol / 4,11 mol/l = 9,08 ml

66,5 ml NaOH